main()//唐子豪
{  
    int a[9],ii=0,i,a1,a2,a3,a4,b1,b2,b3,b4,flag;
    for(i=1;i<=8;i++){
        printf("Please enter [%d]number:",i);
        scanf("%d",&a[i]);
        ii+=a[i];

    }
    printf("* * * * * * * * * * * * * * * * * *\n");
    if(ii%2){
        printf("Sorry they can't be constructed required cube!\n");
        exit(0);

    }
    for(flag=0,a1=1;a1<=8;a1++)
        for(a2=1;a2<=8;a2++)
            if(a2!=a1)
                for(a3=1;a3<=8;a3++)
                    if(a3!=a2&&a3!=a1)
                        for(a4=1;a4<=8;a4++)
                            if(a4!=a3&&a4!=a2&&a4!=a1)
                                for(b1=1;b1<=8;b1++)
                                     if(b1!=a4&&b1!=a3&&b1!=a1)
                                          for(b2=1;b2<=8;b2++)
                                            if(b2!=b1&&b2!=a4&&b2!=a3&b2!=a1)
                                             for(b3=1;b3<=8;b3++)
                                                 if(b3!=b2&&b3!=b1&&b3!=a4&b3!=a3&b3!=a2&b3!=a1)
                                                    for(b4=1;b4<=8;b4++)
                                                        if(b4!=b2&&b4!=b1&&b4!=b3&&b4!=a4&&b4!=a3&&b4!=a2&&b4!=a1)
                                                        if(a[b1]+a[b2]+a[b3]+a[b4]==ii/2&&a[a1]+a[a2]+a[b1]+a[b2]==ii/2&&
                                                        a[a1]+a[a4]+a[b1]+a[b4]==ii/2)
                                                        { flag=1; goto out;}
        out:
            if(flag){
                printf("They can be constructed required cube as follow:\n");
                printf("         /%2d.............../%2d\n",a[a4],a[a3]);
                printf("        %2d/...............%2d/|\n",a[a1],a[a2]);
                prinf("          |      |           |  |\n");
                prinf("          |      |           |  |\n");
                printf("         |      %2d|          |   |%2d",a[b4],a[b3]);
                printf("         /..................-/\n");
                printf("         %2d/................%2d/\n",a[b1],a[b2]);

            }   
    else printf("Sorry they can't be constructed required cube!\n");
    
}                                                       